The number of unpaired electrons in a chromic | vedclass

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(C) The atomic number of $Cr$ is $24$. The ground state electronic configuration of $Cr$ is $(Ar) \ 3d^5 \ 4s^1$.To form the $Cr^{3+}$ ion,we remove $

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$3$

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(C) The atomic number of $Cr$ is $24$. The ground state electronic configuration of $Cr$ is $(Ar) \ 3d^5 \ 4s^1$.To form the $Cr^{3+}$ ion,we remove $3$ electrons: one from the $4s$ orbital and two from the $3d$ orbital.Thus,the electronic configuration of $Cr^{3+}$ is $(Ar) \ 3d^3 \ 4s^0$.In the $3d^3$ configuration,there are $3$ unpaired electrons in the $d$-orbitals.

The number of unpaired electrons in a chromic ion $Cr^{3+}$ (atomic number $= 24$) is

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