The number of unpaired electrons in chromic i | vedclass

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(C) The atomic number of Chromium $(Cr)$ is $24$.Its ground state electronic configuration is $[Ar] 3d^5 4s^1$.To form the chromic ion $(Cr^{3+})$,thr

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$3$

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(C) The atomic number of Chromium $(Cr)$ is $24$.Its ground state electronic configuration is $[Ar] 3d^5 4s^1$.To form the chromic ion $(Cr^{3+})$,three electrons are removed: one from the $4s$ orbital and two from the $3d$ orbital.The electronic configuration of $Cr^{3+}$ becomes $[Ar] 3d^3$.In the $3d^3$ configuration,the three electrons occupy three separate $d$-orbitals singly according to Hund's rule.Therefore,the number of unpaired electrons in $Cr^{3+}$ is $3$.

The number of unpaired electrons in chromic ion $(Cr^{3+})$ is (atomic number of $Cr = 24$)

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