(B) The atomic number of nitrogen $(N)$ is $7$.The electronic configuration of nitrogen is $1s^2, 2s^2, 2p^3$.According to Hund's rule of maximum mult

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(B) The atomic number of nitrogen $(N)$ is $7$.The electronic configuration of nitrogen is $1s^2, 2s^2, 2p^3$.According to Hund's rule of maximum multiplicity,electrons fill the degenerate $p$-orbitals singly before pairing begins.Thus,the $2p$ subshell contains $2p_x^1, 2p_y^1, 2p_z^1$.Therefore,nitrogen has $3$ unpaired electrons.