The octahedral diamagnetic low spin complex a | vedclass

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Question

(D) $(A) [NiCl_4]^{2-}$: $Ni^{2+} = [Ar] 3d^8$. $Cl^-$ is a weak field ligand,so it is paramagnetic,high spin,and tetrahedral.$(B) [CoCl_6]^{3-}$: $Co

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$[Co(NH_3)_6]^{3+}$

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(D) $(A) [NiCl_4]^{2-}$: $Ni^{2+} = [Ar] 3d^8$. $Cl^-$ is a weak field ligand,so it is paramagnetic,high spin,and tetrahedral.$(B) [CoCl_6]^{3-}$: $Co^{3+} = [Ar] 3d^6$. $Cl^-$ is a weak field ligand,so it is paramagnetic,high spin,and octahedral.$(C) [CoF_6]^{3-}$: $Co^{3+} = [Ar] 3d^6$. $F^-$ is a weak field ligand,so it is paramagnetic,high spin,and octahedral.$(D) [Co(NH_3)_6]^{3+}$: $Co^{3+} = [Ar] 3d^6$. $NH_3$ is a strong field ligand,which causes pairing of electrons in $3d$ orbitals. Thus,it is diamagnetic,low spin,and octahedral.

The octahedral diamagnetic low spin complex among the following is

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