The order of decreasing stability of the carb | vedclass

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(B) The stability of carbanions is determined by the inductive effect and resonance effect.$1.$ $C_6H_5CH_2^-$ (Benzyl carbanion) is the most stable d

Vedclass · Accepted Answer

$4 > 3 > 2 > 1$

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(B) The stability of carbanions is determined by the inductive effect and resonance effect.$1.$ $C_6H_5CH_2^-$ (Benzyl carbanion) is the most stable due to resonance stabilization by the phenyl ring.$2.$ Among the alkyl carbanions,stability decreases as the number of electron-donating alkyl groups increases due to the $+I$ effect.$3.$ The order of stability for alkyl carbanions is: primary $(CH_3CH_2^-)$ > secondary $((CH_3)_2CH^-)$ > tertiary $((CH_3)_3C^-)$.$4.$ Combining these,the overall order of decreasing stability is: $C_6H_5CH_2^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$,which corresponds to $4 > 3 > 2 > 1$.

The order of decreasing stability of the carbanions is:
$1.$ $(CH_3)_3C^-$
$2.$ $(CH_3)_2CH^-$
$3.$ $CH_3CH_2^-$
$4.$ $C_6H_5CH_2^-$

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The order of decreasing stability of the carbanions is:$1.$ $(CH_3)_3C^-$$2.$ $(CH_3)_2CH^-$$3.$ $CH_3CH_2^-$$4.$ $C_6H_5CH_2^-$