The order of reaction for which the units of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The general formula for the units of the rate constant $k$ for a reaction of order $n$ is given by $(mol \ L^{-1})^{1-n} \ s^{-1}$.Since $1 \ L^{-

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(C) The general formula for the units of the rate constant $k$ for a reaction of order $n$ is given by $(mol \ L^{-1})^{1-n} \ s^{-1}$.Since $1 \ L^{-1} = 1 \ dm^{-3}$,the unit can be written as $(mol \ dm^{-3})^{1-n} \ s^{-1}$.We are given the unit as $mol \ dm^{-3} \ s^{-1}$,which is equivalent to $(mol \ dm^{-3})^{1} \ s^{-1}$.Comparing the exponents of $(mol \ dm^{-3})$,we get $1-n = 1$,which implies $n = 0$.Therefore,the reaction is a zero-order reaction.

The order of reaction for which the units of rate constant are $mol \ dm^{-3} \ s^{-1}$ is

Similar Questions

Calculate the rate constant of a zero order reaction if it is $90 \%$ completed in $90 \ s$.

What is the unit of $K$ for a zero-order reaction?

The half-life period of a zero order reaction is:

Which of the following graphs represents a zero order reaction?
($a = $ initial concentration of reactant,
$x = $ concentration of reactant consumed,
$t = $ time)

Which of the following reactions end in finite time?

Vedclass Test Series

Exam Paper Generator

Online Exam Module