The order of susceptibility of nucleophilic attack on aldehydes follows the order:

$CH_3CHO + HCN$ $\xrightarrow{\text{H}^+} CH_3CH(OH)CN$ $\xrightarrow{\text{H}_3\text{O}^+} CH_3CH(OH)COOH$. In the above reaction,a chiral center is generated. What will be the nature of the resulting acid?

The most appropriate reagent to distinguish between acetaldehyde and formaldehyde is

What are $A, B, C$ and $D$ in the following cross-aldol condensation reaction?
$\text{Propanal} + \text{Ethanal} \xrightarrow[ii) \ \Delta]{i) \ NaOH} A + B + C + D$
(The products are the four possible $\alpha,\beta$-unsaturated aldehydes formed by self and cross-aldol condensation followed by dehydration.)

The tests performed on compound $X$ and their inferences are:

Test	Inference
$(a)$ $2, 4-DNP$ test	Coloured precipitate
$(b)$ Iodoform test	Yellow precipitate
$(c)$ Azo-dye test	No dye formation

Compound $X$ is:

The starting material is $2,3-\text{dimethylbut-2-ene}$. It undergoes ozonolysis followed by reduction with $Zn/H_2O$ to form product $A$. Product $A$ then reacts with $CH_3MgBr$ followed by hydrolysis to form product $B$. Identify product $B$.