The osmotic pressure of a dilute solution is directly proportional to the

$A$ $40 \text{ g}$ non-electrolyte solute having a molar mass of $180 \text{ g mol}^{-1}$ is dissolved in water to form a solution. If the osmotic pressure of the solution is $2 \text{ atm}$ at $300 \text{ K}$, calculate the volume of the solution in $\text{dm}^3$. $(R = 0.0821 \text{ L atm K}^{-1} \text{mol}^{-1})$ (in $\text{ dm}^3$)

$200 \ mL$ of an aqueous solution of a protein contains its $1.26 \ g$. The osmotic pressure of this solution at $300 \ K$ is found to be $2.57 \times 10^{-3} \ bar$. The molar mass of protein will be ......... $g \ mol^{-1}$.
$(R = 0.083 \ L \ bar \ mol^{-1} \ K^{-1})$

In osmosis:

The solution in which the blood cells retain their normal form is with regard to the blood:

The osmotic pressure of a sugar solution at $300 \ K$ is $2.46 \ atm$. What is the concentration of the solution (in $M$)?