The outer orbitals of $C$ in ethene molecule can be considered to be hybridized to give three equivalent $sp^2$ orbitals. The total number of sigma $(\sigma)$ and pi $(\pi)$ bonds in ethene molecule is
- A$3$ sigma $(\sigma)$ and $2$ pi $(\pi)$ bonds
- B$4$ sigma $(\sigma)$ and $1$ pi $(\pi)$ bonds
- C$5$ sigma $(\sigma)$ and $1$ pi $(\pi)$ bonds
- D$1$ sigma $(\sigma)$ and $2$ pi $(\pi)$ bonds
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Similar Questions
Observe the following statements:
Statement-$I$: Hybridisation is not the same in both ${SF}_6$ and ${BrF}_5$.
Statement-$II$: ${BrF}_5$ is square pyramidal while ${SF}_6$ is octahedral in shape.
The correct answer is:
Statement-$I$: Hybridisation is not the same in both ${SF}_6$ and ${BrF}_5$.
Statement-$II$: ${BrF}_5$ is square pyramidal while ${SF}_6$ is octahedral in shape.
The correct answer is:
Total number of species from the following with central atom utilising $sp^2$ hybrid orbitals for bonding is.................... $NH_3, SO_2, SiO_2, BeCl_2, C_2H_2, C_2H_4, BCl_3, HCHO, C_6H_6, BF_3, C_2H_4Cl_2$
Differentiate between atomic orbitals and hybrid orbitals.
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View SolutionThe hybridisations of the atomic orbitals of nitrogen in $NO_{2}^{-}$,$NO_{2}^{+}$ and $NH_{4}^{+}$ respectively are.
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