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(A) $1$. The circuit consists of a $NAND$ gate, a $NOR$ gate, and an $OR$ gate.$2$. The inputs to the $NAND$ gate are $A$ and $B$. Therefore, its outp

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$\overline{(A \cdot B)} + \overline{(B + C)}$

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(A) $1$. The circuit consists of a $NAND$ gate, a $NOR$ gate, and an $OR$ gate.$2$. The inputs to the $NAND$ gate are $A$ and $B$. Therefore, its output is $\overline{A \cdot B}$.$3$. The inputs to the $NOR$ gate are $B$ and $C$. Therefore, its output is $\overline{B + C}$.$4$. These two outputs are fed into an $OR$ gate. The output of an $OR$ gate is the sum of its inputs.$5$. Thus, the final output $Y = \overline{A \cdot B} + \overline{B + C}$.

The output $Y$ of the given logic circuit is

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