The output across the diode in the given circ | vedclass

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(C) In the given circuit, the diode is connected in parallel with the output terminals. During the positive half cycle of the input $V_m \sin(\omega t

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Would be like a half wave rectifier with negative cycles in output.

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(C) In the given circuit, the diode is connected in parallel with the output terminals. During the positive half cycle of the input $V_m \sin(\omega t)$, the diode is forward-biased. Since an ideal diode acts as a short circuit when forward-biased, the output voltage $V_0$ across the diode becomes $0 \ V$. During the negative half cycle, the diode is reverse-biased. An ideal diode acts as an open circuit when reverse-biased. Therefore, the entire input voltage appears across the output terminals, i.e., $V_0 = V_m \sin(\omega t)$. Thus, the output consists only of the negative half cycles of the input signal, which is characteristic of a half-wave rectifier with negative cycles in the output.

The output across the diode in the given circuit is:

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