The output characteristics of an $n-p-n$ transistor represent, ($I_C =$ collector current, $V_{CE} =$ potential difference between collector and emitter, $I_B =$ base current, $V_{BB} =$ voltage given to base, $V_{BE} =$ the potential difference between base and emitter)
- Achanges in $I_C$ as $I_B$ and $V_{BB}$ are changed
- Bchanges in $I_C$ with changes in $V_{CE}$ ($I_B =$ constant)
- Cchanges in $I_B$ with changes in $V_{CE}$
- Dchange in $I_C$ as $V_{BE}$ is changed
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Similar Questions
The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :
For the transistor circuit shown below,if $\beta = 100$ and the voltage drop between the emitter and base is $0.7 \, V$,then the value of $V_{CE}$ will be......$V$.
Medium
View Solution$A$ change of $0.04 \ V$ takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result,a $20 \ \mu A$ change takes place in the base current and a change of $2 \ mA$ takes place in the collector current. The input resistance and $AC$ current gain are:
DifficultAP EAMCET 2021
View SolutionThe input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.
Easy
View SolutionFor a $CE$ amplifier,current gain is $69$. If the emitter current is $7\, mA$,then the base current and collector current will be:
Difficult
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