The output of a NOR gate is HIGH when | vedclass

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(D) The Boolean expression for a $NOR$ gate is $Y = \overline{A+B}$, where $A$ and $B$ are inputs and $Y$ is the output.The truth table for a $NOR$ ga

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all inputs are $LOW$

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(D) The Boolean expression for a $NOR$ gate is $Y = \overline{A+B}$, where $A$ and $B$ are inputs and $Y$ is the output.The truth table for a $NOR$ gate is:| $A$ | $B$ | $Y = \overline{A+B}$ ||---|---|---|| $0$ | $0$ | $1$ || $0$ | $1$ | $0$ || $1$ | $0$ | $0$ || $1$ | $1$ | $0$ |From the truth table, it is clear that when all inputs ($A$ and $B$) are $LOW$ $(0)$, the output of the $NOR$ gate is $HIGH$ $(1)$.

The output of a $NOR$ gate is $HIGH$ when

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