(D) Let the oxidation number of $Cr$ be $x$. The oxidation number of $NH_3$ is $0$ and the oxidation number of $Cl$ is $-1$. The sum of oxidation numb

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Let the oxidation number of $Cr$ be $x$. The oxidation number of $NH_3$ is $0$ and the oxidation number of $Cl$ is $-1$. The sum of oxidation numbers in a neutral complex is $0$. $x + 6 \times (0) + 3 \times (-1) = 0$ $x - 3 = 0$ $x = +3$ Therefore,the oxidation number of $Cr$ is $+3$.