(C) Let the oxidation number of phosphorus be $x$. In $Ba(H_2PO_2)_2$,the oxidation state of $Ba$ is $+2$,$H$ is $+1$,and $O$ is $-2$. The sum of oxid

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(C) Let the oxidation number of phosphorus be $x$. In $Ba(H_2PO_2)_2$,the oxidation state of $Ba$ is $+2$,$H$ is $+1$,and $O$ is $-2$. The sum of oxidation numbers in a neutral compound is $0$. $1(+2) + 2[2(+1) + x + 2(-2)] = 0$ $2 + 2[2 + x - 4] = 0$ $2 + 2[x - 2] = 0$ $2 + 2x - 4 = 0$ $2x - 2 = 0$ $2x = 2$ $x = +1$