The oxidation state of N in HNO_4 is | vedclass

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(B) $HNO_4$ is peroxynitric acid,which contains one peroxy linkage $(-O-O-)$.Let the oxidation state of $N$ be $x$.The structure is $HO-O-NO_2$.Assign

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$+5$

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(B) $HNO_4$ is peroxynitric acid,which contains one peroxy linkage $(-O-O-)$.Let the oxidation state of $N$ be $x$.The structure is $HO-O-NO_2$.Assigning oxidation states: $H = +1$,$O$ (in $-OH$) $= -2$,$O$ (in peroxy linkage) $= -1$,$O$ (in $NO_2$) $= -2$.Calculation: $(+1) + (-2) + (-1) + x + 2(-2) = 0$$1 - 2 - 1 + x - 4 = 0$$x - 6 = 0$$x = +5$

The oxidation state of $N$ in $HNO_4$ is

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