The oxidation state of chromium in the final product formed in the reaction between $KI$ and acidified $K_{2}Cr_{2}O_{7}$ solution is:

  • A
    $+4$
  • B
    $+3$
  • C
    $+2$
  • D
    $+6$

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Similar Questions

The equivalent weight of $MnSO_4$ is half of its molecular weight when it is converted to

Assign $A, B, C, D$ from given type of reaction.
$Na_{(s)} + H_2O_{(l)} \xrightarrow{R.T.} NaOH + H_2 \uparrow $

Assign $A, B, C, D$ from the given types of reactions:
$A$: Disproportionation reaction.
$B$: Comproportionation reaction.
$C$: Either intermolecular redox reaction or displacement reaction.
$D$: Either thermal combination redox reaction or thermal decomposition redox reaction.
Reaction: $MnO_4^- + H^+ + Br^- \longrightarrow Mn^{2+}(aq.) + Br_2 \uparrow$

Explain the balancing of a redox reaction by the oxidation number method.

For the redox reaction $MnO_4^- + C_2O_4^{2-} + H^{+} \to Mn^{2+} + CO_2 + H_2O$,the correct coefficients of the reactants for the balanced reaction are:
$MnO_4^-$ : $C_2O_4^{2-}$ : $H^{+}$

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