The oxidation state of cobalt in the followin | vedclass

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(D) The given molecule is $Co_2(CO)_8$.In this complex,the ligand $CO$ (carbonyl) is a neutral ligand,meaning its charge is $0$.Since the overall char

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$0$

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(D) The given molecule is $Co_2(CO)_8$.In this complex,the ligand $CO$ (carbonyl) is a neutral ligand,meaning its charge is $0$.Since the overall charge of the molecule $Co_2(CO)_8$ is $0$,we can calculate the oxidation state of $Co$ as follows:Let the oxidation state of $Co$ be $x$.$2x + 8(0) = 0$$2x = 0$$x = 0$Therefore,the oxidation state of cobalt in the molecule is $0$.

The oxidation state of cobalt in the following molecule is

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