The oxidation states of nitrogen in NO,NO_{2} | vedclass

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Question

(A) To find the oxidation state of nitrogen $(N)$ in each species,we use the rule that the oxidation state of oxygen $(O)$ is $-2$.$1$. In $NO_{3}^{-}

Vedclass · Accepted Answer

$NO_{3}^{-} > NO_{2} > NO > N_{2}O$

Vedclass · Answer

(A) To find the oxidation state of nitrogen $(N)$ in each species,we use the rule that the oxidation state of oxygen $(O)$ is $-2$.$1$. In $NO_{3}^{-}$: $x + 3(-2) = -1 \implies x - 6 = -1 \implies x = +5$.$2$. In $NO_{2}$: $x + 2(-2) = 0 \implies x - 4 = 0 \implies x = +4$.$3$. In $NO$: $x + (-2) = 0 \implies x = +2$.$4$. In $N_{2}O$: $2x + (-2) = 0 \implies 2x = 2 \implies x = +1$.Comparing the values: $+5 (NO_{3}^{-}) > +4 (NO_{2}) > +2 (NO) > +1 (N_{2}O)$.Thus,the correct order is $NO_{3}^{-} > NO_{2} > NO > N_{2}O$.

Column-$I$	Column-$II$
$A$. Positively charged ion	$1$. $+7$
$B$. Oxidation number of all neutral atoms	$2$. $-1$
$C$. Oxidation number of hydrogen $(H^+)$	$3$. $+1$
$D$. Oxidation number of fluorine in $NaF$	$4$. $0$
$E$. Negatively charged ion	$5$. Cation
	$6$. Anion

The oxidation states of nitrogen in $NO$,$NO_{2}$,$N_{2}O$ and $NO_{3}^{-}$ are in the order of :

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