The oxidation states of three carbon atoms in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The structure of carbon suboxide $(C_3O_2)$ is $O=C=C=C=O$. In this structure, the two terminal carbon atoms are bonded to oxygen atoms. Since the

Vedclass · Accepted Answer

$+2, 0, +2$

Vedclass · Answer

(A) The structure of carbon suboxide $(C_3O_2)$ is $O=C=C=C=O$. In this structure, the two terminal carbon atoms are bonded to oxygen atoms. Since the oxidation state of oxygen is $-2$, each terminal carbon atom must have an oxidation state of $+2$ to balance the bond. The central carbon atom is bonded to two other carbon atoms, and since there is no electronegativity difference between identical atoms, its oxidation state is $0$. Thus, the oxidation states are $+2, 0, +2$.

The oxidation states of three carbon atoms in carbon suboxide $(C_3O_2)$ respectively are

Similar Questions

The oxidation number of $S$ in $S^{2-}$ is:

The oxidation number of sulphur is $-4$ in

Oxidation number of $S$ in $S_2Cl_2$ is

Which of the following pairs will have different oxidation numbers for oxygen?

The oxidation state of the oxygen atom in potassium superoxide is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module