The oxide that gives H_2O_2 on treatment with | vedclass

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(B) The correct option is $B$,which is $Na_2O_2$.Explanation:$Na_2O_2$ is a peroxide. When it reacts with a dilute acid like $H_2SO_4$,it produces hyd

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$Na_2O_2$

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(B) The correct option is $B$,which is $Na_2O_2$.Explanation:$Na_2O_2$ is a peroxide. When it reacts with a dilute acid like $H_2SO_4$,it produces hydrogen peroxide $(H_2O_2)$:$Na_2O_2 + H_2SO_4 \rightarrow Na_2SO_4 + H_2O_2$Other oxides like $PbO_2$,$MnO_2$,and $TiO_2$ are not peroxides; they are higher oxides that do not contain the peroxide $(-O-O-)$ linkage,and thus they do not yield $H_2O_2$ upon treatment with dilute acids.

The oxide that gives $H_2O_2$ on treatment with a dilute acid is

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