The pair of compounds which cannot exist toge | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Compounds that cannot exist together in an aqueous solution are those that react with each other via an acid-base reaction.$I$. $NaH_2PO_4$ (acidi

Vedclass · Accepted Answer

only $IV$

Vedclass · Answer

(D) Compounds that cannot exist together in an aqueous solution are those that react with each other via an acid-base reaction.$I$. $NaH_2PO_4$ (acidic salt) and $NaHCO_3$ (amphoteric salt) can coexist as they do not react significantly.$II$. $Na_2CO_3$ and $NaHCO_3$ can coexist in equilibrium in aqueous solution.$III$. $NaOH$ (strong base) and $NaH_2PO_2$ (salt of a weak acid and strong base) can coexist.$IV$. $NaHCO_3$ and $NaOH$ react to form $Na_2CO_3$ and $H_2O$:$NaHCO_3 + NaOH \rightarrow Na_2CO_3 + H_2O$.Therefore,they cannot exist together in solution.

The pair of compounds which cannot exist together in aqueous solution is
$I$. $NaH_2PO_4$ and $NaHCO_3$
$II$. $Na_2CO_3$ and $NaHCO_3$
$III$. $NaOH$ and $NaH_2PO_2$
$IV$. $NaHCO_3$ and $NaOH$

Similar Questions

Identify the organism shown in the given figure.

In angiosperms,the functional megaspore develops into which of the following?

$\frac{\sqrt{8+\sqrt{28}}+\sqrt{8-\sqrt{28}}}{\sqrt{8+\sqrt{28}}-\sqrt{8-\sqrt{28}}}$ is equal to

During the depression in freezing point experiment,an equilibrium is established between the molecules of

If $1^{\circ} = \alpha$ radians,then the approximate value of $\cos(60^{\circ} 1^{\prime})$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The pair of compounds which cannot exist together in aqueous solution is$I$. $NaH_2PO_4$ and $NaHCO_3$$II$. $Na_2CO_3$ and $NaHCO_3$$III$. $NaOH$ and $NaH_2PO_2$$IV$. $NaHCO_3$ and $NaOH$