The pair(s) of reagents that yield paramagnet | vedclass

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(D) . $Na$ in excess $NH_3$ forms solvated electrons,which are paramagnetic.$B$. $K + O_2$ (excess) $\rightarrow KO_2$. The superoxide ion $O_2^-$ has

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$A, B, C$

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(D) . $Na$ in excess $NH_3$ forms solvated electrons,which are paramagnetic.$B$. $K + O_2$ (excess) $\rightarrow KO_2$. The superoxide ion $O_2^-$ has one unpaired electron,making it paramagnetic.$C$. $Cu +$ dilute $HNO_3 \rightarrow Cu(NO_3)_2 + NO + H_2O$. $NO$ (nitric oxide) has an odd number of electrons $(15)$,making it paramagnetic.$D$. $O_2 + 2-ethylanthraquinol \rightarrow 2-ethylanthraquinone + H_2O_2$. $H_2O_2$ is diamagnetic.Therefore,the reagents yielding paramagnetic species are $A, B,$ and $C$.

Compound	Uses
$1. CaCO_3$	$a.$ In purification of coal gas
$2. Ca(OH)_2$	$b.$ As an antacid
$3. CaO$	$c.$ In paper and textile industries
$4. Na_2CO_3 \cdot 10H_2O$	$d.$ In glass and leather industries

The pair$(s)$ of reagents that yield paramagnetic species is/are:
$A$. $Na$ and excess of $NH_3$
$B$. $K$ and excess of $O_2$
$C$. $Cu$ and dilute $HNO_3$
$D$. $O_2$ and $2-ethylanthraquinol$

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Compound Uses

$1. CaCO_3$ $a.$ In purification of coal gas

$2. Ca(OH)_2$ $b.$ As an antacid

$3. CaO$ $c.$ In paper and textile industries

$4. Na_2CO_3 \cdot 10H_2O$ $d.$ In glass and leather industries

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The pair$(s)$ of reagents that yield paramagnetic species is/are:$A$. $Na$ and excess of $NH_3$$B$. $K$ and excess of $O_2$$C$. $Cu$ and dilute $HNO_3$$D$. $O_2$ and $2-ethylanthraquinol$