The percentage of $p$-character of the hybrid orbitals in graphite and diamond are respectively
- A$50$ and $75$
- B$67$ and $75$
- C$33$ and $75$
- D$33$ and $25$
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Similar Questions
Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :
Differentiate between atomic orbitals and hybrid orbitals.
Difficult
View SolutionWhich one of the following statements is true for the ammonium ion $(NH_4^+)$?
Medium
View SolutionMatch the species in List-$I$ with their correct hybrid orbitals in List-$II$.
List-$I$ List-$II$ $(1)$ $SF_4$ $(A)$ $sp^3d^2$ $(2)$ $IF_5$ $(B)$ $d^2sp^3$ $(3)$ $NO_2^+$ $(C)$ $sp^3d$ $(4)$ $NH_4^+$ $(D)$ $sp^3$ $(E)$ $sp$
| List-$I$ | List-$II$ |
| $(1)$ $SF_4$ | $(A)$ $sp^3d^2$ |
| $(2)$ $IF_5$ | $(B)$ $d^2sp^3$ |
| $(3)$ $NO_2^+$ | $(C)$ $sp^3d$ |
| $(4)$ $NH_4^+$ | $(D)$ $sp^3$ |
| $(E)$ $sp$ |
Medium
View SolutionIn which of the following species is the hybrid state of the central atom the same?
Difficult
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