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(A) Perimeter of a rectangle $= 2 	imes (8 + 7) = 2 	imes 15 = 30\, cm$.Perimeter of a square $= 2 	imes 30 = 60\, cm$.Side of the square $= \frac{

Vedclass · Accepted Answer

$38.57$

Vedclass · Answer

(A) Perimeter of a rectangle $= 2 	imes (8 + 7) = 2 	imes 15 = 30\, cm$.Perimeter of a square $= 2 	imes 30 = 60\, cm$.Side of the square $= \frac{60}{4} = 15\, cm$.Diameter of the semicircle $= 15\, cm$,so radius $r = \frac{15}{2} = 7.5\, cm$.Circumference of a semicircle $= \pi r + d = \pi r + 2r = r(\pi + 2)$.Using $\pi \approx 3.14159$,Circumference $= 7.5 	imes (3.14159 + 2) = 7.5 	imes 5.14159 \approx 38.5619$.Rounding to two decimal places,we get $38.56\, cm$. (Note: Using $\pi = \frac{22}{7}$,$7.5 	imes (3.1428 + 2) = 7.5 	imes 5.1428 = 38.57\, cm$).

The perimeter of a square is equal to twice the perimeter of a rectangle of length $8\, cm$ and breadth $7\, cm$. What is the circumference of a semicircle whose diameter is equal to the side of the square? (rounded off to the two decimal places) (in $cm$)

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