The period of a simple pendulum is doubled,when

  • A
    Its length is doubled
  • B
    The mass of the bob is doubled
  • C
    Its length is made four times
  • D
    The mass of the bob and the length of the pendulum are doubled

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The time period of a simple pendulum in air is $T$. If the pendulum is immersed in water and executes $SHM$,its time period is $t$. The value of $\frac{T}{t}$ is [density of the bob is $\frac{5000}{3} \ kg \ m^{-3}$ and density of water is $1000 \ kg \ m^{-3}$].

Two simple pendulums of lengths $L_1$ and $L_2$ have time periods $T_1$ and $T_2$ respectively, where $T_1 > T_2$. What is the time period of a simple pendulum of length $(L_1 - L_2)$?

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