The phase difference between the two particles situated on both the sides of a node in a stationary wave is ... $^o$.

For a stationary wave,$Y = 10 \sin \left( \frac{\pi x}{15} \right) \cos (48 \pi t) \text{ cm}$,the distance between a node and the successive antinode is (in $\text{ cm}$)

Standing waves are produced in a $10 \, m$ long stretched string fixed at both ends. If the string vibrates in $5$ segments and the wave velocity is $20 \, m/s$,the frequency is ....... $Hz$.

For the stationary wave $y = 4 \sin \left(\frac{\pi x}{15}\right) \cos (96 \pi t)$,the distance between a node and the next antinode is

The equation of a stationary wave along a stretched string is given by $y = 5 \sin \left( \frac{\pi x}{3} \right) \cos (40 \pi t)$. Here $x$ and $y$ are in $cm$ and $t$ is in seconds. The separation between two adjacent nodes is: (in $cm$)

What are nodes and antinodes?