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(C) The relationship between phase difference $\phi$ and time difference $\Delta t$ is given by $\Delta t = \frac{T}{2\pi} 	imes \phi$.Given frequenc

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$2.5 \ ms$

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(C) The relationship between phase difference $\phi$ and time difference $\Delta t$ is given by $\Delta t = \frac{T}{2\pi} 	imes \phi$.Given frequency $f = 50 \ Hz$,the time period $T = \frac{1}{f} = \frac{1}{50} \ s$.The phase difference $\phi = \frac{\pi}{4}$.Substituting these values into the formula:$\Delta t = \frac{(1/50)}{2\pi} 	imes \frac{\pi}{4} = \frac{1}{50 	imes 2 	imes 4} = \frac{1}{400} \ s$.$\Delta t = 0.0025 \ s = 2.5 \ ms$.

The phase difference between the voltage and the current in an $AC$ circuit is $\pi / 4$. If the frequency is $50 \ Hz$,then this phase difference will be equivalent to a time of:

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