The phenomenon in which a proton flips is

If the energy released per fission of a ${ }_{92}^{235} U$ nucleus is $200 \text{ MeV}$, the energy released in the fission of $0.1 \text{ kg}$ of ${ }_{92}^{235} U$ in kilowatt-hour is:

In the proton-proton cycle, four hydrogen nuclei combine to release energy of ....... $MeV$.

In a fission reaction $_{92}^{236}U \to ^{117}X + ^{117}Y + n + n$,the binding energy per nucleon of $X$ and $Y$ is $8.5\, MeV$,whereas that of $^{236}U$ is $7.6\, MeV$. The total energy liberated will be about . . . . . . $MeV$.

If the energy released in the fission of one nucleus is $200 \, MeV$, then the number of nuclei required per second in a power plant of $16 \, kW$ will be:

Fusion reaction is initiated with the help of