(C) In $B-DNA$,one full turn of the helical strand contains $10$ base pairs.Each base pair is stacked at a distance of $3.4 \; \mathring{A}$ from the

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(C) In $B-DNA$,one full turn of the helical strand contains $10$ base pairs.Each base pair is stacked at a distance of $3.4 \; \mathring{A}$ from the next.Therefore,the pitch of the $DNA$ (the length of one complete turn) is calculated as $3.4 \; \mathring{A} \times 10 = 34 \; \mathring{A}$.