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(C) The static plate resistance $(R_p)$ of a diode is defined as the ratio of the plate voltage $(V_p)$ to the plate current $(i_p)$ at a specific ope

Vedclass · Accepted Answer

$333.3$

Vedclass · Answer

(C) The static plate resistance $(R_p)$ of a diode is defined as the ratio of the plate voltage $(V_p)$ to the plate current $(i_p)$ at a specific operating point $P$.From the given graph,at point $P$,the plate voltage $V_p = 50 \, V$ and the plate current $i_p = 150 \, mA = 150 	imes 10^{-3} \, A$.The static plate resistance is given by:$R_p = \frac{V_p}{i_p} = \frac{50}{150 	imes 10^{-3}} \, \Omega$$R_p = \frac{50}{0.15} \, \Omega = \frac{5000}{15} \, \Omega = 333.33 \, \Omega$.Therefore,the static plate resistance is approximately $333.3 \, \Omega$.

The plate characteristic curve of a diode in the space charge limited region is as shown in the figure. The slope of the curve at point $P$ is $5.0 \, mA/V$. The static plate resistance of the diode will be ...... $\Omega$.

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