The point where the line $\frac{x - 1}{2} = \frac{y - 2}{-3} = \frac{z + 3}{4}$ meets the plane $2x + 4y - z = 1$ is:

  • A
    $(3, -1, 1)$
  • B
    $(3, 1, 1)$
  • C
    $(1, 1, 3)$
  • D
    $(1, 3, 1)$

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