The points A(9,0), B(9,6), C(-9,6) and D(-9,0 | vedclass

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(C) To determine the shape,we calculate the lengths of the sides using the distance formula $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$.$AB = \sqrt{(9-9)^2

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rectangle

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(C) To determine the shape,we calculate the lengths of the sides using the distance formula $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$.$AB = \sqrt{(9-9)^2 + (6-0)^2} = \sqrt{0^2 + 6^2} = 6$$BC = \sqrt{(-9-9)^2 + (6-6)^2} = \sqrt{(-18)^2 + 0^2} = 18$$CD = \sqrt{(-9-(-9))^2 + (0-6)^2} = \sqrt{0^2 + (-6)^2} = 6$$DA = \sqrt{(9-(-9))^2 + (0-0)^2} = \sqrt{18^2 + 0^2} = 18$Since opposite sides are equal ($AB = CD = 6$ and $BC = DA = 18$) and the adjacent sides are perpendicular (as the sides are parallel to the coordinate axes),the figure is a rectangle.

The points $A(9,0), B(9,6), C(-9,6)$ and $D(-9,0)$ are the vertices of a

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