The population of a town is 123,456,789. It i | vedclass

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(C) Let the initial population be $P = 123,456,789$.After the first year,the population becomes $P 	imes (1 + 0.10) = 1.1P$.After the second year,the

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$23 \frac{13}{15}\%$

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(C) Let the initial population be $P = 123,456,789$.After the first year,the population becomes $P 	imes (1 + 0.10) = 1.1P$.After the second year,the population becomes $1.1P 	imes (1 + 0.20) = 1.1P 	imes 1.2 = 1.32P$.After the third year,the population becomes $1.32P 	imes (1 + 0.30) = 1.32P 	imes 1.3 = 1.716P$.The total percentage increase over three years is $(1.716P - P) / P 	imes 100 = 71.6\%$.The average percentage increase per year is the total percentage increase divided by $3$.Average percentage increase $= 71.6 / 3 = 716 / 30 = 23 \frac{26}{30} = 23 \frac{13}{15}\%$.

The population of a town is $123,456,789$. It increases by $10\%$ during the first year,$20\%$ during the second year,and $30\%$ during the third year. What is the average percentage increase during the three years?

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