The position-time graph for the motion of a car is given below.
$(i)$ How far did the car travel in the time interval $2 \, s$ to $6 \, s$?
(ii) During which interval of time was its speed greater?
(iii) Calculate the average speed of the car.

(N/A) $(i)$ At $t = 2 \, s$,position $x = 0 \, m$. At $t = 6 \, s$,position $x = 5 \, m$. Therefore,distance traveled $= 5 \, m - 0 \, m = 5 \, m$.
(ii) The speed is represented by the slope of the position-time graph. The slope is steeper between $2 \, s$ and $4 \, s$ compared to the interval between $4 \, s$ and $6 \, s$. Thus,the speed was greater during the interval $2 \, s$ to $4 \, s$.
(iii) Average speed $= \frac{\text{Total distance covered}}{\text{Total time taken}}$.
Total distance $= 5 \, m$.
Total time $= 6 \, s - 2 \, s = 4 \, s$.
Average speed $= \frac{5 \, m}{4 \, s} = 1.25 \, m/s$.