The possible number of stereoisomers for 5-ph | vedclass

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(B) The structure of $5-$phenylpent$-4-$en$-2-$ol is $C_6H_5-CH=CH-CH_2-CH(OH)-CH_3$.
There are two stereogenic units in this molecule:
$1$. The car

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$4$

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(B) The structure of $5-$phenylpent$-4-$en$-2-$ol is $C_6H_5-CH=CH-CH_2-CH(OH)-CH_3$.
There are two stereogenic units in this molecule:
$1$. The carbon-carbon double bond $(C=C)$ at position $4$,which can exhibit geometrical isomerism ($cis$ or $trans$).
$2$. The chiral carbon atom at position $2$,which can exhibit optical isomerism ($R$ or $S$ configuration).
Since the molecule does not have a plane of symmetry,the total number of stereoisomers is given by $2^n$,where $n$ is the number of stereogenic units.
Here,$n = 2$,so the number of stereoisomers $= 2^2 = 4$.

List-$I$ (Pair of Compounds)	List-$II$ (Type of Isomers)
$A$. $2-$Methylpropene and but$-1-$ene	$I$. Stereoisomers
$B$. $Cis-$but$-2-$ene and $trans-$but$-2-$ene	$II$. Position isomers
$C$. $2-$Butanol and diethyl ether	$III$. Chain isomers
$D$. But$-1-$ene and but$-2-$ene	$IV$. Functional group isomers

The possible number of stereoisomers for $5-$phenylpent$-4-$en$-2-$ol is $.............$

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