The possible number of stereoisomers of the p | vedclass

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(C) The reaction of an aldehyde with hydroxylamine $(H_2N - OH)$ at $pH = 4.5$ produces an oxime. The product is: $Ph - CH = CH - CH(CH_3) - CH = N -

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$8$

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(C) The reaction of an aldehyde with hydroxylamine $(H_2N - OH)$ at $pH = 4.5$ produces an oxime. The product is: $Ph - CH = CH - CH(CH_3) - CH = N - OH$. To find the number of stereoisomers,we identify the stereogenic units in the product: $1.$ The $C = C$ double bond (can exist as $E$ or $Z$ configurations). $2.$ The chiral carbon atom $-CH(CH_3)-$ (can exist as $R$ or $S$ configurations). $3.$ The $C = N$ double bond of the oxime (can exist as $syn$ or $anti$ configurations). Since the molecule is unsymmetrical and has $n = 3$ stereogenic units,the total number of stereoisomers is $2^n = 2^3 = 8$.

The possible number of stereoisomers of the product of the following reaction would be: $Ph - CH = CH - CH(CH_3) - CHO \xrightarrow[pH = 4.5]{H_2N - OH}$ ?

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