The potential difference between points C and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the potential difference between points $C$ and $D$,we first need to determine the current flowing through the resistor between $C$ and $D

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) To find the potential difference between points $C$ and $D$,we first need to determine the current flowing through the resistor between $C$ and $D$.Applying Kirchhoff's Current Law $(KCL)$ at junction $C$:The sum of currents entering the junction must equal the sum of currents leaving the junction.Let $I_{BC}$ be the current flowing from $B$ to $C$,$I_{CF}$ be the current flowing from $C$ to $F$,$I_{CG}$ be the current flowing from $C$ to $G$,and $I_{CD}$ be the current flowing from $C$ to $D$.First,find $I_{BC}$ using $KCL$ at junction $B$:$I_{AB} + I_{EB} = I_{BC}$$4 \ A + 1.8 \ A = I_{BC}$$I_{BC} = 5.8 \ A$Now,apply $KCL$ at junction $C$:$I_{BC} = I_{CF} + I_{CG} + I_{CD}$$5.8 \ A = 1.3 \ A + 1 \ A + I_{CD}$$5.8 \ A = 2.3 \ A + I_{CD}$$I_{CD} = 5.8 \ A - 2.3 \ A = 3.5 \ A$The potential difference between $C$ and $D$ is given by Ohm's Law:$V_{CD} = I_{CD} 	imes R_{CD}$$V_{CD} = 3.5 \ A 	imes 8 \ \Omega = 28 \ V$.

The potential difference between points $C$ and $D$ of the electrical circuit shown in the figure is (in $V$)

Similar Questions

For the network shown in the figure,the value of the current $i$ is:

In the circuit shown,the end $A$ is at potential $V_0$ and end $B$ is grounded. The electric current $I$ indicated in the circuit is

Why is the circuit configuration known as a Wheatstone bridge?

Resistances are joined as shown in the figure. In the balanced condition, the current $I$ drawn from the battery is (in $\text{ A}$)

The figure shows a network of currents. The values of the currents are shown in the figure. What is the value of current $I$ in $A$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module