(B) The power of a point $P(x_1, y_1)$ with respect to a circle $(x - h)^2 + (y - k)^2 = r^2$ is given by the formula $P = (x_1 - h)^2 + (y_1 - k)^2 -

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(B) The power of a point $P(x_1, y_1)$ with respect to a circle $(x - h)^2 + (y - k)^2 = r^2$ is given by the formula $P = (x_1 - h)^2 + (y_1 - k)^2 - r^2$. Given the point $P(-3, 7)$,the centre $(h, k) = (3, 7)$,and the radius $r = 2$. Substituting these values into the formula: $P = (-3 - 3)^2 + (7 - 7)^2 - 2^2$ $P = (-6)^2 + (0)^2 - 4$ $P = 36 + 0 - 4$ $P = 32$. Thus,the power of the point is $32$.

Class 11 Mathematics 10-1.Circle and System of Circles Equations of circle

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The power of the point $(-3, 7)$ with respect to a circle,with centre $(3, 7)$ and radius $2$,is

AP EAMCET 2017 All AP EAMCET

A
$49$
B
$32$
C
$36$
D
$25$

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10-1.Circle and System of Circles

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