The primary and secondary coils of a transfor | vedclass

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(C) The induced electromotive force $(emf)$ in the primary coil is given by Faraday's law of induction: $E_P = \frac{d\phi}{dt}$.Given $\phi = \phi_0

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(C) The induced electromotive force $(emf)$ in the primary coil is given by Faraday's law of induction: $E_P = \frac{d\phi}{dt}$.Given $\phi = \phi_0 + 4t$,we have $E_P = \frac{d}{dt}(\phi_0 + 4t) = 4 	ext{ volts}$.For an ideal transformer,the ratio of the secondary voltage $(E_S)$ to the primary voltage $(E_P)$ is equal to the ratio of the number of turns in the secondary coil $(N_S)$ to the number of turns in the primary coil $(N_P)$: $\frac{E_S}{E_P} = \frac{N_S}{N_P}$.Substituting the given values: $\frac{E_S}{4} = \frac{1500}{50}$.$\frac{E_S}{4} = 30$.Therefore,$E_S = 30 	imes 4 = 120 	ext{ volts}$.

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