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(C) The reaction of an alkene with $HBr$ in the presence of a peroxide follows the anti-Markovnikov addition mechanism (Kharasch effect or peroxide ef

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$BrCH_2CH_2(CH_2)_8COOH$

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(C) The reaction of an alkene with $HBr$ in the presence of a peroxide follows the anti-Markovnikov addition mechanism (Kharasch effect or peroxide effect).In this reaction,the $Br^\bullet$ radical adds to the carbon atom of the double bond that has more hydrogen atoms,resulting in the formation of the less substituted radical.For the reactant $CH_2=CH(CH_2)_8COOH$,the terminal carbon $(CH_2=)$ has two hydrogen atoms,while the internal carbon $(-CH=)$ has one.Therefore,the $Br$ atom attaches to the terminal $CH_2$ group,and the $H$ atom attaches to the internal $CH$ group.The product formed is $BrCH_2CH_2(CH_2)_8COOH$.

The principal organic product formed in the following reaction is
$CH_2=CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}}$

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The principal organic product formed in the following reaction is$CH_2=CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}}$