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(B) Given,the probability of event $A$ occurring in one trial is $P(A) = 0.4$.Therefore,the probability of event $A$ not occurring in one trial is $P(

Vedclass · Accepted Answer

$0.784$

Vedclass · Answer

(B) Given,the probability of event $A$ occurring in one trial is $P(A) = 0.4$.Therefore,the probability of event $A$ not occurring in one trial is $P(\bar{A}) = 1 - 0.4 = 0.6$.For $n = 3$ independent trials,the probability that event $A$ does not happen at all is $P(	ext{none}) = (P(\bar{A}))^3 = (0.6)^3 = 0.216$.The probability that event $A$ happens at least once is given by $P(	ext{at least once}) = 1 - P(	ext{none})$.$P(	ext{at least once}) = 1 - 0.216 = 0.784$.

The probability of an event $A$ happening in one trial is $0.4$. The probability that the event $A$ happens at least once in three independent trials is

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