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(D) Let $P(T)$ be the probability of a test occurring in a class, $P(T) = 1/5$.Let $P(T')$ be the probability of no test occurring, $P(T') = 1 - 1/5 =

Vedclass · Accepted Answer

$9/25$

Vedclass · Answer

(D) Let $P(T)$ be the probability of a test occurring in a class, $P(T) = 1/5$.Let $P(T')$ be the probability of no test occurring, $P(T') = 1 - 1/5 = 4/5$.The student is absent for $2$ classes. The student misses at least one test if a test occurs in the first class, the second class, or both.It is easier to calculate the complement: the probability that the student misses no tests.The student misses no tests if no test occurs in either of the $2$ classes.$P(	ext{misses no tests}) = P(T') 	imes P(T') = (4/5) 	imes (4/5) = 16/25$.Therefore, the probability that the student misses at least one test is $1 - P(	ext{misses no tests}) = 1 - 16/25 = 9/25$.

The probability that a teacher will give an unannounced test during any class meeting is $1/5$. If a student is absent twice, then the probability that the student will miss at least one test is

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