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(D) Brine is an aqueous solution of $NaCl$. $NaCl_{(aq)} \rightarrow Na^+_{(aq)} + Cl^-_{(aq)}$ At the cathode,water is reduced in preference to $Na^+

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$HCl$

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(D) Brine is an aqueous solution of $NaCl$. $NaCl_{(aq)} \rightarrow Na^+_{(aq)} + Cl^-_{(aq)}$ At the cathode,water is reduced in preference to $Na^+$ ions: $2H_2O_{(l)} + 2e^- \rightarrow H_{2(g)} + 2OH^-_{(aq)}$ At the anode,chloride ions are oxidized: $2Cl^-_{(aq)} \rightarrow Cl_{2(g)} + 2e^-$ The remaining ions in the solution are $Na^+$ and $OH^-$,which combine to form $NaOH_{(aq)}$. Therefore,$H_2$,$Cl_2$,and $NaOH$ are produced,while $HCl$ is not formed during the electrolysis of brine.

The product,which is not obtained during the electrolysis of brine solution,is

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