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Question

(A) $1$. The starting material is $o$-xylene. Oxidation with $KMnO_4/OH^-$ followed by acidification $(H^+)$ yields phthalic acid $(C_6H_4(COOH)_2)$.$

Vedclass · Accepted Answer

Phthalimide

Vedclass · Answer

(A) $1$. The starting material is $o$-xylene. Oxidation with $KMnO_4/OH^-$ followed by acidification $(H^+)$ yields phthalic acid $(C_6H_4(COOH)_2)$.$2$. Phthalic acid reacts with $NH_3$ to form ammonium phthalate,which upon heating gives phthalamide $(C_6H_4(CONH_2)_2)$.$3$. Further strong heating of phthalamide leads to the loss of $NH_3$ to form phthalimide $(C_6H_4(CO)_2NH)$.$4$. Thus,the final product $(C)$ is phthalimide.

The product $(C)$ will be

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