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(C) The reaction of ethylene oxide (oxirane) with a Grignard reagent $(RMgI)$ involves the nucleophilic attack of the alkyl group $(R^-)$ on one of th

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$R - CH_2 - CH_2 - OH$

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(C) The reaction of ethylene oxide (oxirane) with a Grignard reagent $(RMgI)$ involves the nucleophilic attack of the alkyl group $(R^-)$ on one of the carbon atoms of the epoxide ring,leading to ring opening.The reaction proceeds as follows:$C_2H_4O + RMgI 	o R - CH_2 - CH_2 - OMgI$Subsequent hydrolysis of the intermediate yields the primary alcohol:$R - CH_2 - CH_2 - OMgI + H_2O 	o R - CH_2 - CH_2 - OH + MgI(OH)$Thus,the product $A$ is $R - CH_2 - CH_2 - OH$.

The product $A$ in the following reaction is

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