The product $D$ of the reaction is:
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_2O} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$

  • A
    $CH_3CH_2NH_2$
  • B
    $CH_3CN$
  • C
    $HCONH_2$
  • D
    $CH_3CONH_2$

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