The product (P) of the following reaction: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction involves two steps: $1$. The first step uses $Br_2/NaOH$,which is the condition for the Hofmann bromamide degradation reaction. This

Vedclass · Accepted Answer

Vedclass · Answer

(C) The reaction involves two steps: $1$. The first step uses $Br_2/NaOH$,which is the condition for the Hofmann bromamide degradation reaction. This reaction converts an amide group $(-CONH_2)$ into a primary amine group $(-NH_2)$. $2$. The starting material is methyl $2-(carbamoylmethyl)benzoate$. The $-CONH_2$ group is converted to $-CH_2NH_2$. $3$. The intermediate formed is methyl $2-(aminomethyl)benzoate$. $4$. In the second step,heating $(\Delta)$ causes an intramolecular cyclization (nucleophilic acyl substitution) where the $-NH_2$ group attacks the ester carbonyl group $(-COOCH_3)$,resulting in the loss of a methanol molecule $(-CH_3OH)$ and the formation of a cyclic amide (lactam). $5$. The final product $(P)$ is $isoindolin-1-one$.

The product $(P)$ of the following reaction:

Similar Questions

The reagent$(s)$ used for the conversion of benzene diazonium hydrogensulphate to benzene is/are:

Sulfanilic acid is a/an ....

What is the nature of an aqueous solution of methylamine?

What is the correct decreasing order of basic strength?

The compound obtained by the reaction between primary amine and aldehyde is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module