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Question

(C) The reaction sequence is as follows:$1$. Reduction of benzonitrile $(C_6H_5CN)$ with $LiAlH_4$ followed by $H_2O$ gives benzylamine $(C_6H_5CH_2NH

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Benzyl alcohol

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(C) The reaction sequence is as follows:$1$. Reduction of benzonitrile $(C_6H_5CN)$ with $LiAlH_4$ followed by $H_2O$ gives benzylamine $(C_6H_5CH_2NH_2)$.$2$. Treatment of benzylamine with $NaNO_2 + HCl$ at low temperature $(0-5 \ ^\circ C)$ forms unstable benzyl diazonium chloride $(C_6H_5CH_2N_2^+Cl^-)$.$3$. Benzyl diazonium chloride rapidly decomposes to form a benzyl carbocation $(C_6H_5CH_2^+)$,which reacts with water $(H_2O)$ to yield benzyl alcohol $(C_6H_5CH_2OH)$.

The product formed from the following reaction sequence is?

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