The product formed in the above reaction is

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(D) The reaction of an alkyne with sodium in liquid ammonia $(Na/Liq. NH_3)$ is known as Birch reduction,which results in the stereoselective anti-add

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(D) The reaction of an alkyne with sodium in liquid ammonia $(Na/Liq. NH_3)$ is known as Birch reduction,which results in the stereoselective anti-addition of hydrogen to the triple bond to form a $trans$-alkene. The double bond present in the cyclohexene ring remains unaffected under these conditions. Therefore,the product is a $trans$-alkene. Thus,option $(D)$ is correct.

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